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Consider a point charge Q = 4 × 10⁻⁷ C. The electric potential at a point 9 cm from it is closest to
A4 × 10⁵ V
B4 × 10⁶ V
C4 × 10⁴ V
D4 × 10³ V
Answer & Solution
Correct answer: C. 4 × 10⁴ V
V = kQ/r = (9×10⁹)(4×10⁻⁷)/(0.09) = 3.6×10³/0.09 = 4×10⁴ V. Worked out as Example 2.1(a) in the chapter.
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