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A charge Q = 4 × 10⁻⁷ C is at the origin. The work done in bringing a small test charge q = 2 × 10⁻⁹ C from infinity to a point 9 cm away is approximately
A8 × 10⁻⁵ J
B8 × 10⁻³ J
C8 × 10⁻⁷ J
D8 × 10⁻⁹ J
Answer & Solution
Correct answer: A. 8 × 10⁻⁵ J
V at 9 cm = 4×10⁴ V. W = qV = (2×10⁻⁹)(4×10⁴) = 8×10⁻⁵ J. Path-independent.
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