alleryTwo point charges of 2 μC each are placed 1 m apart in vacuum. The magnitude of the Coulomb force between them is closest to
A3.6 × 10⁻² N
B9.0 × 10⁻³ N
C9.0 N
D3.6 × 10⁻³ N
Answer & Solution
Correct answer: A. 3.6 × 10⁻² N
We have F = (1/4πε₀)·q₁q₂/r².
That is F = 9×10⁹ × (2×10⁻⁶)² / 1².
That is F = 9×10⁹ × 4×10⁻¹².
So F = 3.6×10⁻² N.
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