Using the junction in the figure, Kirchhoff's Current Law gives which relation? 
A$I_1+I_2=I_3+I_4+I_5+I_6$
B$I_1+I_2+I_3=I_4+I_5+I_6$
C$I_1+I_4+I_5=I_2+I_3+I_6$
D$I_1+I_2+I_3+I_4+I_5+I_6=0$
Answer & Solution
Correct answer: B. $I_1+I_2+I_3=I_4+I_5+I_6$
In the figure, $I_1$, $I_2$, and $I_3$ enter the node, while $I_4$, $I_5$, and $I_6$ leave it. By Kirchhoff's Current Law, sum of currents entering equals sum leaving, so $I_1+I_2+I_3=I_4+I_5+I_6$.
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