Using the junction in the figure, Kirchhoff's Current Law gives which relation? 
A$I_1+I_2=I_3+I_4+I_5+I_6$
B$I_1+I_2+I_3=I_4+I_5+I_6$
C$I_1+I_4+I_5=I_2+I_3+I_6$
D$I_1+I_2+I_3+I_4+I_5+I_6=0$
Answer & Solution
Correct answer: B. $I_1+I_2+I_3=I_4+I_5+I_6$
In the figure, $I_1$, $I_2$, and $I_3$ enter the node, while $I_4$, $I_5$, and $I_6$ leave it. By Kirchhoff's Current Law, sum of currents entering equals sum leaving, so $I_1+I_2+I_3=I_4+I_5+I_6$.
Related questions
The reactance of a capacitor $C$ at frequency $f$ in an a.c. circuit is:A bird perched on a single high voltage wire is unharmed because:The two conservation laws embodied in Kirchhoff's rules are conservation of:The resistance offered by the cell itself is called:Which device detects the current in a Wheatstone bridge?In a Wheatstone bridge, the source is connected across the:The Wheatstone bridge is made up of how many resistors?At a junction, the current entering equals the current: