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If in the junction relation $I_1+I_2+I_3=I_4+I_5+I_6$, the values are $I_1=2\,\text{A}$, $I_2=3\,\text{A}$, $I_3=1\,\text{A}$, $I_4=4\,\text{A}$, and $I_5=0.5\,\text{A}$, then $I_6$ is

A$0.5\,\text{A}$
B$1.0\,\text{A}$
C$1.5\,\text{A}$
D$2.0\,\text{A}$
Answer & Solution
Correct answer: C. $1.5\,\text{A}$
Using KCL, $I_1+I_2+I_3=I_4+I_5+I_6$. So $2+3+1=4+0.5+I_6$, giving $6=4.5+I_6$. Hence $I_6=1.5\,\text{A}$.
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