The electric field intensity at any point **inside** a uniformly charged hollow conducting sphere is:
A$q / (4\pi\varepsilon_0 R^2)$
B$\sigma R / \varepsilon_0$
CZero
D$\sigma / \varepsilon_0$
Answer & Solution
Correct answer: C. Zero
Inside a hollow charged sphere a Gaussian surface encloses zero charge, so by Gauss's law E·4πr² = 0 and hence E = 0 everywhere inside.
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