alleryStart learning →An equivalence relation on a set splits it into disjoint
Aidentity maps
Bordered products
Cequivalence classes
Dunions of pairs
Answer & Solution
Correct answer: C. equivalence classes
Each equivalence relation partitions the underlying set into disjoint equivalence classes.
Keep practising Sets, Relations and Functions
Browse all Sets, Relations and Functions questions for CA Foundation, or explore more Quantitative Aptitude topics.
Related questions
As x grows large, (4x^3 + x)/(2x^3 - 7) tends toThe limit of (sqrt(x) - 2)/(x - 4) as x approaches 4 isAs x tends to infinity, (3x^2 - 5)/(6x^2 + x) approachesFor f(x) = |x|, the left limit, right limit and f(0) at x = 0 are allA function is continuous at c if the limit of f(x) as x tends to c equalsLet f(x) = x^2 for x < 1 and f(x) = 2x - 1 for x >= 1. At x = 1, f isf(x) = kx + 1 for x <= 2 and f(x) = 3 for x > 2 is continuous at 2 when k isLet f(x) = (x^2 - 9)/(x - 3) for x not equal to 3. For f to be continuous at 3, f(3) must