R = {(1,1), (2,2), (3,3), (1,2)} on {1, 2, 3} is not an equivalence relation because it is not
Aa subset
Btransitive
Creflexive
Dsymmetric
Answer & Solution
Correct answer: D. symmetric
It holds (1,2) but lacks (2,1), so symmetry fails while reflexivity and transitivity hold.
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