Pascal's rule states that nCr + nC(r - 1) equals
A(n + 1)Cr
BnC(r + 1)
C(n - 1)C(r - 1)
D(n - 1)Cr
Answer & Solution
Correct answer: A. (n + 1)Cr
Adding two adjacent entries of a row of Pascal's triangle gives the entry below them, (n + 1)Cr.
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