A coil of N turns, each of radius R and current I, has centre field:
Amu-0 I / 2NR
BN mu-0 I / 2R
Cmu-0 N I R / 2
Dmu-0 I / 2R
Answer & Solution
Correct answer: B. N mu-0 I / 2R
The N turns each add the same field at the centre, so B = N mu-0 I / 2R.
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