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At equilibrium in a moving coil galvanometer, the deflection phi satisfies:
Ak phi = N I A B
Bphi = k N I A B
Ck = phi N I A B
Dphi = k / N I A B
Answer & Solution
Correct answer: A. k phi = N I A B
The magnetic torque N I A B is balanced by the spring torque k phi.
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