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A circular coil of 10 cm radius carries 5 A. What is B at its centre (mu-0 = 4 pi x 10^-7)?

A3.14 x 10^-4 T
B6.28 x 10^-5 T
C3.14 x 10^-5 T
D1.57 x 10^-5 T
Answer & Solution
Correct answer: C. 3.14 x 10^-5 T
B = mu-0 I / 2R = 4 pi x 10^-7 x 5 / 0.2 = 3.14 x 10^-5 T.
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