For the curve xy = 8, the origin is moved to (2, 1). What is the transformed equation?
Ax'y' + x' + 2y' = 6
Bx'y' - x' - 2y' = 6
Cx'y' + x' + 2y' = 8
Dx'y' + 2x' + y' = 6
Answer & Solution
Correct answer: A. x'y' + x' + 2y' = 6
With x = x' + 2 and y = y' + 1, the product expands to x'y' + x' + 2y' + 2 = 8, which gives x'y' + x' + 2y' = 6.
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