If the origin is moved to the point (h, k) with axes kept parallel, what is the old x in terms of the new x'?
Ax = x' - h
Bx = x' + k
Cx = x' + h
Dx = h - x'
Answer & Solution
Correct answer: C. x = x' + h
The new origin sits at x = h in the old frame, so the old abscissa is the new one plus h.
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