A circular loop of area $0.02\,\text{m}^2$ is placed with its plane making an angle of $60^\circ$ with a uniform magnetic field of magnitude $0.5\,\text{T}$. The magnetic flux linked with the loop is:

Magnetic flux $\Phi = B A \cos\theta$, where $\theta$ is the angle between $\vec{B}$ and the area vector (the normal to the loop). The plane makes $60^\circ$ with $\vec{B}$, so the normal makes $30^\circ$ with $\vec{B}$. $\Phi = 0.5 \times 0.02 \times \cos 30^\circ = 0.01 \times 0.866 = 8.66 \times 10^{-3}\,\text{Wb}$.