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A plane passes through (1, 2, 3) and has normal direction ratios 2, 3, 4. What is its equation?
A2x + 3y + 4z = 12
B2x + 3y + 4z = 20
Cx + 2y + 3z = 20
D2x + 3y + 4z = 9
Answer & Solution
Correct answer: B. 2x + 3y + 4z = 20
The plane is 2(x-1) + 3(y-2) + 4(z-3) = 0, which simplifies to 2x + 3y + 4z = 20.
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