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Which plane has the vector (4, -3, 2) as a normal?
A3x + 4y + 2z = 1
B4x + 3y - 2z = 1
C4x - 3y + 2z = 1
D2x - 3y + 4z = 1
Answer & Solution
Correct answer: C. 4x - 3y + 2z = 1
In Ax + By + Cz = D the coefficients (A, B, C) form a normal, so 4x - 3y + 2z = 1 fits.
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