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What is the perpendicular distance from the origin to the plane 2x + 3y + 6z = 14?
A1 unit
B4 units
C3 units
D2 units
Answer & Solution
Correct answer: D. 2 units
The distance is 14 divided by the square root of 4 + 9 + 36, which is 14/7 = 2.
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