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For acute angles A and B with sin A = 3/5 and cos B = 5/13, sin(A + B) is:
A33/65
B56/65
C16/65
D63/65
Answer & Solution
Correct answer: D. 63/65
cos A = 4/5 and sin B = 12/13, so sin(A + B) = (3/5)(5/13) + (4/5)(12/13) = 63/65.
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