Home › AP EAPCET (Engineering) › Mathematics › Coordinate Geometry: Locus › A point sees the segment from (1, 2) to (5, 4) a…
A point sees the segment from (1, 2) to (5, 4) at a right angle. Its path is
Ax² + y² - 6x - 6y + 13 = 0
Bx² + y² - 6x - 6y + 5 = 0
Cx² + y² + 6x + 6y + 13 = 0
Dx² + y² - 3x - 3y + 13 = 0
Answer & Solution
Correct answer: A. x² + y² - 6x - 6y + 13 = 0
(x - 1)(x - 5) + (y - 2)(y - 4) = 0 expands to x² + y² - 6x - 6y + 13 = 0, the circle on AB as diameter.
Related questions
Every circle in one Apollonian family meets every circle of the other familyIn one Apollonian family, each circle is the locus of points whose ratio of distances to tThe locus of the inequality 2x + 3y - 6 < 0 is the part of the planeThe Mandelbrot set is described as the connectedness locus of a family ofThe set of singular points of an algebraic variety is called itsThe set of critical points of a differentiable function is itsIn the old view, a circle was the locus of a point at a given distance fromWhich phrase best defines the locus of a point?