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The locus of the inequality 2x + 3y - 6 < 0 is the part of the plane
Aon the line 2x + 3y = 6
Babove the line 2x + 3y = 6
Cbelow the line 2x + 3y = 6
Dinside a circle at the origin
Answer & Solution
Correct answer: C. below the line 2x + 3y = 6
The origin gives -6 < 0, so the region on the origin's side, below the line 2x + 3y = 6, is the locus.
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