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Points at twice the distance from the origin as from (3, 0) lie on
Ax² + y² - 8x + 12 = 0
Bx² + y² - 6x + 9 = 0
Cx² + y² + 8x + 12 = 0
Dx² + y² - 4x + 3 = 0
Answer & Solution
Correct answer: A. x² + y² - 8x + 12 = 0
x² + y² = 4[(x - 3)² + y²] simplifies to 3x² + 3y² - 24x + 36 = 0, that is x² + y² - 8x + 12 = 0.
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