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Which hyperbola has foci (±5, 0) and focal difference 6 in size?
Ax²/25 - y²/9 = 1
Bx²/16 - y²/9 = 1
Cx²/9 - y²/16 = 1
Dx²/9 + y²/16 = 1
Answer & Solution
Correct answer: C. x²/9 - y²/16 = 1
2a = 6 gives a = 3, and c = 5 gives b² = 25 - 9 = 16, so x²/9 - y²/16 = 1.
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