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Asymptotes y = ±(3/4)x and vertex (4, 0) give the hyperbola
Ax²/4 − y²/3 = 1
Bx²/16 − y²/9 = 1
Cx²/9 − y²/16 = 1
Dx²/16 − y²/12 = 1
Answer & Solution
Correct answer: B. x²/16 − y²/9 = 1
a = 4 and b/a = 3/4 give b = 3, so x²/16 − y²/9 = 1.
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