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The tangents of slope 2 to the hyperbola x²/9 − y²/16 = 1 are
Ay = 2x ± 4√5
By = 2x ± 5
Cy = 2x ± 2√5
Dy = 2x ± 52
Answer & Solution
Correct answer: C. y = 2x ± 2√5
c² = a²m² − b² = 36 − 16 = 20, so c = ±2√5.
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