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For y²/16 − x²/9 = 1, the lines approached far away are
Ay = ±(3/4)x
By = ±(16/9)x
Cy = ±x
Dy = ±(4/3)x
Answer & Solution
Correct answer: D. y = ±(4/3)x
For a vertical hyperbola the slopes are ±a/b = ±4/3.
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