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The vertices of y²/16 − x²/9 = 1 are
A(0, ±4)
B(±3, 0)
C(0, ±3)
D(±4, 0)
Answer & Solution
Correct answer: A. (0, ±4)
The y² term is positive with a² = 16, so the vertices are (0, ±4).
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