Home › AP EAPCET (Engineering) › Mathematics › Coordinate Geometry: Hyperbola › The directrices of x²/9 − y²/16 = 1 are how far …
The directrices of x²/9 − y²/16 = 1 are how far apart?
A10/3
B3/5
C9/5
D18/5
Answer & Solution
Correct answer: D. 18/5
Directrices x = ±9/5 are 2a²/c = 18/5 apart.
Related questions
A particle with total energy greater than zero moves under an inverse square attraction. IThe midpoints of a family of parallel chords of a hyperbola lie on aThe eccentricity e of any hyperbola satisfiesThe locus of a point whose distances from two fixed points differ by a constant is aA general point on the hyperbola x²/a² − y²/b² = 1 in parametric form isThe tangents of slope 2 to the hyperbola x²/9 − y²/16 = 1 areThe line y = mx + c touches the hyperbola x²/a² − y²/b² = 1 only ifThe tangent to x²/a² − y²/b² = 1 at the point (x1, y1) has equation