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Home › AP EAPCET (Engineering) › Mathematics › Coordinate Geometry: Hyperbola › The foci of y²/9 − x²/16 = 1 are at

The foci of y²/9 − x²/16 = 1 are at

A(0, ±7)
B(0, ±5)
C(±5, 0)
D(±7, 0)
Answer & Solution
Correct answer: B. (0, ±5)
The y² term is positive so the axis is vertical, and c² = 9 + 16 = 25 gives (0, ±5).
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