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Home › AP EAPCET (Engineering) › Mathematics › Coordinate Geometry: Hyperbola › Where are the foci of x²/16 − y²/9 = 1?

Where are the foci of x²/16 − y²/9 = 1?

A(±4, 0)
B(±7, 0)
C(±3, 0)
D(±5, 0)
Answer & Solution
Correct answer: D. (±5, 0)
c² = a² + b² = 16 + 9 = 25, so the foci lie at (±5, 0).
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