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Using u = 1 + x², the function x/(1 + x²) is integrated over [0, 1]. What is the result?

A(ln 2)/2
Bln 2
C2 ln 2
Dπ/4
Answer & Solution
Correct answer: A. (ln 2)/2
Putting u = 1 + x² gives (1/2)∫ from 1 to 2 of du/u = (1/2)ln 2.
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