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In ∫₀² x(x² + 1)³ dx, the substitution u = x² + 1 changes the limits to
A1 to 3
B0 to 4
C1 to 5
D0 to 2
Answer & Solution
Correct answer: C. 1 to 5
At x = 0 we get u = 1 and at x = 2 we get u = 5, so the new limits are 1 and 5.
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