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Home › TS EAPCET (Engineering) › Mathematics › Integration by Substitution › Between 0 and 1, the integral of 1 over the squa…

Between 0 and 1, the integral of 1 over the square root of 1 minus x squared equals

Aπ
B1
Cπ/2
Dπ/4
Answer & Solution
Correct answer: C. π/2
The antiderivative sin⁻¹x gives sin⁻¹1 − sin⁻¹0 = π/2.
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