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Two rounds of integration by parts are needed for x squared times eˣ. What is the outcome?
Aeˣ(x² − 2x + 2) + C
Beˣ(x² − 2x) + C
Ceˣ(x² − 2) + C
Deˣ(x² + 2x + 2) + C
Answer & Solution
Correct answer: A. eˣ(x² − 2x + 2) + C
Applying integration by parts twice gives x²eˣ − 2xeˣ + 2eˣ.
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