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Splitting 1/((x − 1)(x − 2)) into partial fractions for x > 2 gives which integral?
Aln|(x − 2)/(x − 1)| + C
Bln|x − 1| + ln|x − 2| + C
Cln|(x − 1)(x − 2)| + C
Dln|(x − 1)/(x − 2)| + C
Answer & Solution
Correct answer: A. ln|(x − 2)/(x − 1)| + C
Partial fractions give 1/(x − 2) − 1/(x − 1), whose integral is ln|x − 2| − ln|x − 1|.
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