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For the integrand eˣ(1/x − 1/x²), which antiderivative holds?
Aeˣ ln x + C
Beˣ/x + C
Ceˣ/x² + C
D−eˣ/x + C
Answer & Solution
Correct answer: B. eˣ/x + C
Taking f = 1/x gives f′ = −1/x², so the integrand is eˣ(f + f′) and the integral is eˣ f = eˣ/x.
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