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Which function has derivative 1/(1 + x²)?
Aln(1 + x²)
Btan⁻¹x
Csec⁻¹x
Dsin⁻¹x
Answer & Solution
Correct answer: B. tan⁻¹x
The standard result is that d/dx of tan⁻¹x equals 1/(1 + x²), so tan⁻¹x + C is the integral.
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