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Resolving 1/((x-1)(x-2)) into partial fractions, the numerator over (x-1) is
A1
B-2
C2
D-1
Answer & Solution
Correct answer: D. -1
Setting x = 1 in 1 = A(x-2) + B(x-1) gives 1 = -A, so A = -1.
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