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Rewrite 1/(x²-5x+6) as a difference of two simple fractions.
A1/(x-3) - 1/(x-2)
B1/(x-2) - 1/(x-3)
C1/(x-2) + 1/(x-3)
D2/(x-2) - 1/(x-3)
Answer & Solution
Correct answer: A. 1/(x-3) - 1/(x-2)
Since x²-5x+6 = (x-2)(x-3) and (x-2) - (x-3) = 1, the difference of reciprocals works.
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