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A 60 W lamp filament of emissivity 0.5 and area 5 x 10^-5 m^2 loses all its energy by radiation. What is its temperature?

AAbout 1500 K
BAbout 2550 K
CAbout 3500 K
DAbout 5000 K
Answer & Solution
Correct answer: B. About 2550 K
T^4 = 60 / (0.5 x 5.67e-8 x 5e-5) = 4.23e13, giving T of about 2550 K.
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