alleryStart learning →A blackbody radiates with its peak at a wavelength of 2.897 micrometres. What is its temperature?
A500 K
B1000 K
C2000 K
D5800 K
Answer & Solution
Correct answer: B. 1000 K
T = b / lambda-max = 2.897e-3 / 2.897e-6 = 1000 K.
Keep practising Kinetic Theory of Gases and Radiation
Browse all Kinetic Theory of Gases and Radiation questions for MHT-CET, or explore more Physics topics.
Related questions
Two blackbodies of equal area are at absolute temperatures in the ratio 1:3. What is the rA 60 W lamp filament of emissivity 0.5 and area 5 x 10^-5 m^2 loses all its energy by radiA blackbody of area 200 square cm at 127 degrees Celsius radiates for one minute. How muchFor a body that is not a perfect blackbody, the radiated power per unit area is given by wWho proposed the empirical T^4 radiation law in 1879?In Stefan's law, radiant power per unit area goes as what?Wien's displacement law is useful for estimating what about distant stars?Sun's emission peaks near 4995 angstrom. Which spectral region?