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A plane is 7 units from the origin with normal cosines 2/7, 3/7, 6/7. The foot of the perpendicular is

A(2, 3, 6)
B(14, 21, 42)
C(2/7, 3/7, 6/7)
D(7, 7, 7)
Answer & Solution
Correct answer: A. (2, 3, 6)
The foot N is (pl, pm, pn) = (7 x 2/7, 7 x 3/7, 7 x 6/7) = (2, 3, 6).
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