alleryStart learning →The plane through (1, 2, 3) with normal vector 2i - j + 4k is
A2x - y + 4z = 8
B2x - y + 4z = 12
C2x + y + 4z = 16
Dx - 2y + 3z = 12
Answer & Solution
Correct answer: B. 2x - y + 4z = 12
2(x - 1) - (y - 2) + 4(z - 3) = 0 simplifies to 2x - y + 4z = 12.
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