Home › AP EAPCET (Engineering) › Mathematics › Limits › Let h(x) = (x^2 - 25)/(x - 5). What does h(x) ap…
Let h(x) = (x^2 - 25)/(x - 5). What does h(x) approach as x tends to 5?
AEqual to 25
BEqual to 5
CEqual to 0
DEqual to 10
Answer & Solution
Correct answer: D. Equal to 10
Factorising x^2 - 25 as (x-5)(x+5) leaves x + 5 = 10.
Related questions
A continuous function on a closed interval [a, b] attains a maximum by theWhich definition was introduced to formalise continuity?By the squeeze theorem, the limit of x^2 cos(1/x) as x tends to 0 isIf f(x) = 2x + 1 for x < 1 and f(x) = ax + 2 for x at least 1 is continuous, a equalsf(x) = x sin(1/x) for x not 0 is made continuous at 0 by setting f(0) tof(x) = |x| is continuous at 0 but at 0 it isEvery differentiable function at a point is alsoA function is right-continuous at c if no jump occurs when x approaches c from the