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By the squeeze theorem, the limit of x^2 cos(1/x) as x tends to 0 is
Aequal to 1
Bdoes not exist
Cequal to -1
Dequal to 0
Answer & Solution
Correct answer: D. equal to 0
Since |cos(1/x)| is at most 1, the product lies between -x^2 and x^2, both tending to 0.
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