Area enclosed by y² = 12x and its latus rectum (square units) is
A36
B12
C24
D48
Answer & Solution
Correct answer: C. 24
For y² = 4ax the enclosed area is 8a²/3; here a = 3, giving 24.
Keep practising Application of Definite Integration
Browse all Application of Definite Integration questions for MHT-CET, or explore more Mathematics topics.
Related questions
The area between y² = 4ax and its latus rectum isIntegrating in y, the area between x = y², the Y-axis and y from 0 to 2 isBecause x² is even, its area from −1 to 1 is double that over [0, 1], namelyThe parabolas y² = 4x and x² = 4y intersect at the pointsIf ∫f(x)dx = φ(x), the area under f from x = a to b (f ≥ 0) isBy symmetry, an ellipse has an area equal to how many times its first-quadrant area?Which integral gives the area enclosed by x = g(y), the Y-axis, y = c and y = d?If f(x) ≥ g(x) on [a, b], the area between the curves is the integral of