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The parabolas y² = 4x and x² = 4y intersect at the points

A(0, 0) and (4, 0)
B(4, 4) only
C(0, 0) and (4, 4)
D(0, 0) and (2, 2)
Answer & Solution
Correct answer: C. (0, 0) and (4, 4)
Substituting y = x²/4 gives x⁴ = 64x, so x = 0 or x = 4, and the points are (0, 0) and (4, 4).
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