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Put t = tan^-1 x. What does e^(tan^-1 x)/(1 + x^2) integrate to?

Atan^-1 x e^x + c
Blog(1 + x^2) + c
Ce^(tan^-1 x)/2 + c
De^(tan^-1 x) + c
Answer & Solution
Correct answer: D. e^(tan^-1 x) + c
Put t = tan^-1 x so dt = dx/(1 + x^2); the integral of e^t is e^t.
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