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Splitting 1/(x(x+1)) into two fractions, what is its antiderivative?

Alog|x(x + 1)| + c
Blog|x/(x + 1)| + c
C-1/(2x + 1) + c
Dlog|(x + 1)/x| + c
Answer & Solution
Correct answer: B. log|x/(x + 1)| + c
Partial fractions give 1/x - 1/(x+1), which integrates to log|x/(x+1)|.
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