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Using t = log x, what is the integral of sin(log x) over x?

A-cos(log x) + c
B-sin(log x) + c
Ccos(log x) + c
Dsin(log x) + c
Answer & Solution
Correct answer: A. -cos(log x) + c
Put t = log x so dx/x = dt; the integral of sin t is -cos t.
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